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Find the tangent line to the contour line

** Graph a function ** Be

1voto

Anon User Points 0
1 = x ^ 2-y ^ 2; which is a hyperbola; having az as constant, work on the level surface as if it were R2. I can clear y: y = √ (x ^ 2-1); for (-∞; -1 \] U \ [1; + ∞); derive: y '= x / √ (x ^ 2-1); for the point x = √5; y '= √ 5/2; y = y0 + k \ * (√5) / 2; as y0 = 2: y = 2 + k \ * (√5) / 2; in the point-vector form; or: 2 = (√5) \ * (√5) / 2 + b; 2 = (5/2) + b; b = 2- (5/2); b = (-1/2); y = \ [(√5) / 2 \] x - (1/2); o: 2y = (√5) x -1; o: 0 = 2y - (√5) x +1.

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